25 ++ p(x)=3x solution 372150-P(x)=3x solution
Solution set = {15 ≤ x < 5} The solution set can be graphed on the number line as Question 12 Solve and graph the solution set of (i) 2x – 9 < 7 and 3x 9 ≤ 25, x ∈ R (ii) 2x – 9 ≤ 7 and 3x 9 > 25, x ∈ I (iii) x 5 ≥ 4(x – 1) and 3 – 2x < 7, x ∈ R Solution Question 13 Solve and graph the solution set of (i) 3x(iv) p(x)=kx 2 –3xk Solution If x1 is a factor of p(x), then p(1) = 0 By Factor Theorem ⇒ k(1) 2 –3(1)k = 0 ⇒ k−3k = 0 ⇒ 2k−3 = 0 ⇒ k= 3/2 4 Factorize (i) 12x 2 –7x1 Solution Using the splitting the middle term method, We have to find a number whose sum = 7 and product =1×12 = 12If p(x) is a third degree polynomial and q(x) is a fourth degree polynomial then find the degree of p(x) × q(x) Answer i p(x) = x 2 3x 1 , q(x) = 2x – 4

If P X X3 3x2 5x 3 And G X X2 2 Find Remainder Mathematics Topperlearning Com T7tfrb44
P(x)=3x solution
P(x)=3x solution-If P is the solution set of – 3x 4 < 2x – 3, x ∈ N and Q is the solution set of 4x – 5 < 12, x ∈ W, find (i) P ∩ Q (ii) Q – P Answer 33 (i) – 3 x 4 < 2 x – 3 – 3x – 2x < – 3 – 4 => – 5x < – 7 Question 34 A = {x 11x – 5 > 7x 3, x ∈R} and B = {x 18x – 9 ≥ 15 12x, x ∈R}Is x = 5 a solution of the quadratic equation x 2 – 2x – 15 = 0?



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Remember that if f(x) = Ax^n, then f ' (x) = nAx^(n1) With this in mind, we have P(x) = 3x^2 5x^3 7x^4 3x^5 So P ' (x) = 6x 15x^2 28x^3 15x^4Simplifying p (x) = 3x 14 Multiply p * x px = 3x 14 Reorder the terms px = 14 3x Solving px = 14 3x Solving for variable 'p' Move all terms containing p to the left, all other terms to the right Divide each side by 'x' p = 14x 1 3 Simplifying p = 14x 1 3 Reorder the terms p = 3 14x 1Swap sides so that all variable terms are on the left hand side 3x1=y 3x − 1 = y Add 1 to both sides Add 1 to both sides 3x=y1 3x = y 1 Divide both sides by 3 Divide both sides by 3
Ie say the root is x,then x>=0 As per the question,one of the three roots is 2/3 if all three roots are real,then (2/3) cannot be one of the roots Please check your question and post againPrabhat Edit The three roots (whether real or not) can be found by equating p(x) to zero and then solving the trinomialYou can solve as many equations as you like completely free If you need detailed stepbystep answers you'll have to sign up for Mathway's premium service (provided by a third party)Here, we are given three terms, First term (a 1) = 2xSecond term (a 2) = x 10 Third term (a 3) = 3x 2We need to find the value of x for which these terms are in APSo, in an AP the difference of two adjacent terms is always constant
Find all real zeros of P(x) If neither of these were the instructions, post again and this time give the instructions as to what you are supposed to do with P(x) P(x) = x 5 3x 3 2x 6 x 5 and 3x 3 are both positive, so there is no sign change going from x 5 to 3x 3 3x 3 and 2x are both positive, so there is no sign change going from 3x 3 to 2x 2x is positive and 6 is negative, so that is 1 sign change going from 2x to 6 So there is exactly 1 positive zero of P(x)Solution 2(1) t> Solution 2(2) Solution 2(3) Solution 3 If we divide the total number of chocolates that the student had (x 4 – 3x 3 5x 2 8x 5) by the number of chocolates received by each friend (x 2 – 1), the quotient will give the number of friends and the remainder will give the number of chocolates left over for his teacher Thus, the number of friends = x 2 – 3x 6If p(x)= x 2 – 2√2x1, then find the value of p(2√2) Solution Put x = 2√2 in p(x), we obtain p(2√2) = (2√2) 2 – 2√2(2√2) 1 = (2√2) 2 – (2√2) 2 1 = 1 Question 4 Find the value of m, if x 4 is a factor of the polynomial x 2 3x m Solution Let p(x) = x 2 3x m Since (x 4) or (x – (4)} is a factor of p



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All the solutions of Polynomials Mathematics explained in detail by experts to help students prepare for their CBSE exams R S Aggarwal and V Aggarwal Solutions for Class 9 Mathematics CBSE, 2 Polynomials When p(x) = x 3 3x 2 4x 32 is divided by (x 2), the remainder is (a) 0 (b) 32 (c) 36 (d) 4 Solution 18StepbyStep Solutions Use stepbystep calculators for chemistry, calculus, algebra, trigonometry, equation solving, basic math and more Gain more understanding of your homework with steps and hints guiding you from problems to answers!X^45x^24=0 \sqrt{x1}x=7 \left3x1\right=4 \log _2(x1)=\log _3(27) 3^x=9^{x5} equationcalculator 3x5=14 en Related Symbolab blog posts High School Math Solutions – Quadratic Equations Calculator, Part 1 A quadratic equation is a second degree polynomial having the general form ax^2 bx c = 0, where a



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If p(x) is a third degree polynomial and q(x) is a fourth degree polynomial then find the degree of p(x) × q(x) Answer i p(x) = x 2 3x 1 , q(x) = 2x – 4Here, P=y 2 ,Q=xy , R= x(z2y) Hence the general solution is f(x 2 y 2, yzy 2)=0 3Solve(3z4y)p(4x2z)q=2y3x Soln Given (3z4y)p(4x2z)q=2y3x This equation of the form Ppq=R Here, P= (3z4y) ,Q=(4x2z) , R= 2y3x Again use Lagrangian multipliers 2,3,4, 2x3y4z=b Hence the general solution is, F(x 2 y 2 z 2 , 2x3y4z)=0Solution Let p (x) = 3x 3 11x 2 34x 106 p (x) in standard form Coefficients are 3 11 34 106 q(x) = x – 3, its zero x = 3 Synthetic division Quotient is 3x 2 x 94, it is compared with the given quotient 3x 2 ax b Coefficient of x is a = Constant term is b = 94 Remainder r = 3


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The remainder is zero when f(x) is divided by (x – a) f(a) = 0 The solution to f(x) = 0 is a The zero of the function f(x) is a Example Determine whether x 1 is a factor of the following polynomials a) 3x 4 x 3 – x 2 3x 2 b) x 6 2x(x – 1) – 4 Solution a) Let f(x) = 3x 4 x 3 – x 2 3x 2 f(–1) = 3(–1)4 (–1Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historySolution x 2 – 2x – 15 = 0 For x = 5 to be solution of the given quadratic equation it should satisfy the equation So, substituting x = 5 in the given equation, we get LHS = (5) 2 – 2(5) – 15 = 25 – 10 – 15 = 0 = RHS



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Ex 2 2 4 Find The Zero Of The Polynomial In Each Of Ex 2 2
3 Find the indicated derivative for each function Show your work (Sec 26) Find y000, y= 4x4 x2 7 Solution y0= 16x3 2x y00= 48x2 2 y000= 96x Find d2f dx2, where f(x) = xsinx Solution f0(x) = xcosx sinx f00(x) = cosx xsinx cosx= 2cosx xsinx Find r(4), where r(x) = 1=x Solution r0(x) = 1=x2 r00(x) = 2=x3 r000(x) = 6=x4 r(4)(x) = 24=x5 4 Find a tangent line through the curve 2x 2Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorSolve any equation with this free calculator!



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